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SSC CGL Mensuration Notes: 2D & 3D Formulas, Examples & Practice

Quantitative Aptitude • SSC CGL Tier 1

Mensuration is the most formula-heavy chapter in SSC CGL Quant — and one of the most predictable. The shapes never change, the formulas never change, and the questions are usually a direct application of one formula. If you can recall the formulas under pressure, the marks are practically free.

The official syllabus lists everything from triangles and circles through cubes, cuboids, cylinders, cones, spheres, hemispheres and right pyramids. This chapter covers the full 2D and 3D list in the order you should learn them — 2D first, because every 3D formula is built on a 2D base.

No derivations, no theory fluff — just the formulas, how to choose between them (CSA vs TSA is where most marks die), and worked examples showing the exact steps SSC-style questions expect.

Key Concepts & Formulas

Triangle — perimeter and area

Perimeter is the length of the boundary; area is the surface covered. A triangle's area is half the product of base and height, where the height must be perpendicular to that base. For a triangle whose three sides are known but no height is given, Heron's formula takes over: compute the semi-perimeter s, then the area is the square root of s(s-a)(s-b)(s-c).

Formulas:

Rectangle, square, parallelogram, trapezium

The rectangle and square are the easiest shapes to score on: area is just length times breadth (or side squared), and the perimeter is the round-trip distance. Two facts people forget: the diagonal of a square is side x sqrt(2), and the area of a rhombus equals half the product of its diagonals.

Formulas:

Circle — area and circumference

For a circle, the radius is the star of the show — nearly every formula uses it, not the diameter. Area is pi x r^2 and the circumference (perimeter) is 2 x pi x r. In SSC, use pi = 22/7 when the radius is a multiple of 7 and pi = 3.14 otherwise. For a sector of angle theta, take theta/360 of the full circle's area or circumference.

Formulas:

Cube and cuboid

A cube is a box with all edges equal; a cuboid has three different edges. Total surface area counts every face, volume counts the space inside. For the cuboid, the surface formula 2(lb + bh + hl) comes from the three distinct face pairs. The space diagonal of a cuboid — useful when the question involves the longest rod that fits inside — is sqrt(l^2 + b^2 + h^2).

Formulas:

Cylinder and cone

A cylinder is a circle stretched along a height: the curved (lateral) surface is 2 x pi x r x h, and adding the two circular caps gives the total surface area. A cone is one-third of the cylinder with the same base and height — its curved surface uses the slant height l = sqrt(r^2 + h^2), not the vertical height. That one substitution, h vs l, is where most cone marks are lost.

Formulas:

Sphere and hemisphere

A sphere's surface area is exactly four times the area of its great circle: 4 x pi x r^2. Its volume is (4/3) x pi x r^3. A hemisphere (half a sphere) has a curved surface of 2 x pi x r^2 — but its TOTAL surface area adds the flat circular base, making 3 x pi x r^2. If the question says 'total surface area of a hemisphere' and you answer 2 x pi x r^2, you have missed the base.

Formulas:

Solved Examples

Example 1. A square has side 12 cm. A rectangle has length 15 cm and breadth 8 cm. Which has the larger area, and by how much?
  1. Square area = 12 x 12 = 144 sq cm
  2. Rectangle area = 15 x 8 = 120 sq cm
  3. The square is larger by 144 - 120 = 24 sq cm

Answer: 144 sq cm

Example 2. Find the area and the circumference of a circle of radius 7 cm.
  1. Area = pi x r^2 = (22/7) x 7 x 7 = 22 x 7 = 154 sq cm
  2. Circumference = 2 x pi x r = 2 x (22/7) x 7 = 44 cm

Answer: 154 sq cm; 44 cm

Example 3. A triangle has sides 13 cm, 14 cm and 15 cm. Find its area.
  1. Semi-perimeter s = (13 + 14 + 15)/2 = 42/2 = 21
  2. Area = sqrt(21 x (21-13) x (21-14) x (21-15)) = sqrt(21 x 8 x 7 x 6)
  3. 21 x 8 = 168; 7 x 6 = 42; 168 x 42 = 7056; sqrt(7056) = 84 sq cm

Answer: 84 sq cm

Example 4. A cuboid measures 8 cm x 6 cm x 5 cm. Find its volume and total surface area.
  1. Volume = 8 x 6 x 5 = 240 cubic cm
  2. TSA = 2(lb + bh + hl) = 2(8x6 + 6x5 + 5x8) = 2(48 + 30 + 40) = 2 x 118 = 236 sq cm

Answer: 240 cubic cm; 236 sq cm

Example 5. A cylinder has radius 7 cm and height 10 cm. Find its volume and total surface area.
  1. Volume = pi x r^2 x h = (22/7) x 49 x 10 = 22 x 7 x 10 = 1540 cubic cm
  2. TSA = 2 x pi x r x (r + h) = 2 x (22/7) x 7 x 17 = 44 x 17 = 748 sq cm

Answer: 1540 cubic cm; 748 sq cm

Practice Questions

Q1. The side of a square is 15 cm. Find its area.
  1. 200 sq cm
  2. 215 sq cm
  3. 225 sq cm
  4. 250 sq cm
Show Answer & Explanation

Answer: 225 sq cm
Area = side^2 = 15 x 15 = 225 sq cm.

Q2. Find the circumference of a circle of radius 14 cm.
  1. 84 cm
  2. 88 cm
  3. 92 cm
  4. 96 cm
Show Answer & Explanation

Answer: 88 cm
Circumference = 2 x (22/7) x 14 = 2 x 44 = 88 cm.

Q3. A triangle has base 18 cm and height 12 cm. Find its area.
  1. 96 sq cm
  2. 104 sq cm
  3. 108 sq cm
  4. 112 sq cm
Show Answer & Explanation

Answer: 108 sq cm
Area = (1/2) x 18 x 12 = 9 x 12 = 108 sq cm.

Q4. The side of a cube is 6 cm. Find its volume.
  1. 196 cubic cm
  2. 200 cubic cm
  3. 216 cubic cm
  4. 224 cubic cm
Show Answer & Explanation

Answer: 216 cubic cm
Volume = 6^3 = 216 cubic cm.

Q5. A cylinder has radius 7 cm and height 3 cm. Find its volume.
  1. 440 cubic cm
  2. 452 cubic cm
  3. 462 cubic cm
  4. 474 cubic cm
Show Answer & Explanation

Answer: 462 cubic cm
Volume = (22/7) x 7^2 x 3 = 22 x 7 x 3 = 462 cubic cm.

Common Traps (galtiyan jo marks katwati hain)

FAQs

Which formulas get confused most often?

The cone and the hemisphere are the two big ones: cone uses slant height l (not h) for surface area, and a hemisphere's total surface area is 3 x pi x r^2 (the flat base counts). Also check whether the question wants CSA or TSA — SSC mixes both deliberately.

Should I always use pi = 22/7?

Only when the radius is a multiple of 7. With other numbers, use 3.14 — or look at the options: if they are in terms of pi (like 120 pi), keep pi symbolic and avoid decimals entirely.

Does SSC ask more 2D or 3D mensuration?

Roughly equally, with 2D slightly more common. The smart play: lock down 2D perfectly (it feeds 3D questions too, since every 3D formula contains a 2D base), then learn the 3D list.

How do I verify my mensuration answer quickly?

First sanity check: surface areas are square units, volumes are cubic units — if your 'volume' comes out in sq cm, something went wrong. Then check radius vs diameter, h vs slant height, and that 3D answers are in the right ballpark compared to the options.

Disclaimer: For the latest official exam pattern, always verify on ssc.gov.in. NaukriRoz is not a government website.